To determine the correct amperage of the Miniature Circuit Breaker (MCB) required for a 1.5-ton split air conditioner, you need to know the rated power (in watts) or the current (in amperes) of the AC unit. The power rating of an AC is typically mentioned on its nameplate or in the user manual. The power rating is usually given in terms of "watts" or "volt-amperes" (VA).
However, if you only have the cooling capacity (1.5 tons) and not the power rating, we can still estimate the amperage based on typical values.
A 1.5-ton air conditioner typically has a cooling capacity of around 18,000 BTU per hour. As an estimate, the power consumption (in watts) for a 1.5-ton split AC can be around 1500 to 1800 watts.
Now, to calculate the amperage required for the 1.5-ton AC unit, we can use the formula:
Amperage (A) = Power (W) / Voltage (V)
Assuming the standard voltage is 230 volts (common in many countries):
Amperage (A) = 1500 watts (or 1800 watts) / 230 volts ≈ 6.52 A (or 7.83 A)
So, for a 1.5-ton split air conditioner, you would need an MCB with a rated current of around 7 to 8 amperes. MCBs typically come in standard current ratings like 6A, 8A, 10A, and so on. In this case, a 8A MCB would be appropriate for the 1.5-ton split AC.
Please note that these are rough estimates, and the actual power consumption of the AC unit may vary based on its make, model, and efficiency. It is always best to consult the manufacturer's specifications or a qualified electrician to ensure you select the correct MCB for your specific AC unit.