The required kVA (kilovolt-ampere) rating for a voltage stabilizer depends on the specific power requirements of the air conditioner and the voltage fluctuations in your area. Generally, a 1.5-ton split air conditioner has a cooling capacity of around 5,000 to 6,000 BTU (British Thermal Units) per hour.
To determine the appropriate kVA rating for a voltage stabilizer, you'll need to consider the power consumption of the air conditioner. Typically, a 1.5-ton split AC unit can consume around 1,500 to 1,800 watts of power during operation. However, it's important to refer to the manufacturer's specifications or the label on the air conditioner for the exact power consumption.
Once you know the power consumption in watts, you can convert it to kilovolt-amperes (kVA) by dividing the wattage by the power factor. The power factor is a value that represents the efficiency of power consumption and is typically between 0.9 and 1.0 for air conditioners.
Here's an example calculation:
Let's assume the power consumption of your 1.5-ton split air conditioner is 1,500 watts, and the power factor is 0.9.
Power in kVA = Power in watts / Power factor Power in kVA = 1,500 watts / 0.9 Power in kVA ≈ 1,667 VA / 900 VA Power in kVA ≈ 1.85 kVA
In this example, a voltage stabilizer with a rating of approximately 1.85 kVA would be suitable for your 1.5-ton split air conditioner. Keep in mind that it's always best to consult with a qualified electrician or refer to the manufacturer's guidelines to ensure you select the correct rating for your specific air conditioner and local voltage conditions.